Average bond order of $C - C$ bond in $C_{6} H_{6}$ is:

1

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2

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1.5

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1.33

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Solution

The correct option is B $1.5$
Bond order= $\frac{n o . o f b o n d s i n c l u d i n g π b o n d s}{n o . o f c e n t r a l a t o m s}$
$= \frac{9}{6} = 1.5$
or
Average of total bonds= $\frac{2 + 1 + 2 + 1 + 2 + 1}{6}$ = $\frac{9}{6}$ $= 1.5$

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