Average daily wage of 50 workers of a factory was Rs. 200. Each worker is given a raise of Rs. 20. What is the new average daily wage?

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Solution

Increase in wages of each worker = Rs. 20

Total increase in wages = 50 $\times$ 20 = Rs. 1,000

Total wages after increase in wages = 10,000 + 1,000 = Rs. 11,000

New average daily wage = $\frac{\sum X}{N} = \frac{11, 000}{50} = R s .220$

Thus, mean wage will increase by Rs.20.

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Average daily wage of 50 workers of a factory was Rs 200 with a Standard Deviation of Rs 40. Each worker is given a raise of Rs 20. What is the new average daily wage and Standard Deviation? Have the wages become more or less uniform?

Q. An average daily wages of

10

workers in a factory '

A

' is Rs.

30

and an average daily wages of

20

workers in a factory '

B

' is Rs.

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. Find the average daily wages of all workers of both the factories.

Q. The average of daily wages for the workers of the two factories combined is

No.of wage earners	Factory A 250	Factory B 200
Average daily wage	Rs.2.00	Rs.2.50

Factory A	Factory B
No. of wage earners $250$ Average daily wage Rs. $2.00$	$200$ Rs. $2.50$

The average of daily wages for the earners of the two factories combined is

	Factory A	Factory B
No. of wage earners	$250$	$200$
Average daily wage	Rs. $2.00$	Rs. $2.50$

Average of daily wages for the earners of the factories combined is

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Average daily wage of 50 workers of a factory was Rs. 200. Each worker is given a raise of Rs. 20. What is the new average daily wage?

Increase in wages of each worker = Rs. 20 Total increase in wages = 50 × 20 = Rs. 1,000 Total wages after increase in wages = 10,000 + 1,000 = Rs. 11,000 New average daily wage = ∑XN=11,00050=Rs.220 Thus, mean wage will increase by Rs.20.

Increase in wages of each worker = Rs. 20

Total increase in wages = 50 $\times$ 20 = Rs. 1,000

Total wages after increase in wages = 10,000 + 1,000 = Rs. 11,000

New average daily wage = $\frac{\sum X}{N} = \frac{11, 000}{50} = R s .220$

Thus, mean wage will increase by Rs.20.