Average free flow speed and the jam density observed on a road stretch are 60 km/h and 120 vehicles/ km, respectively. For a linear speed density relationship, the maximum flow on the road stretch (in vehicles/h) is

1800

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Solution

The correct option is A 1800
$V_{f} = 60 k m / h$
$k_{j} = 120 v e h / k m$
$q_{m a x} = \frac{V_{f} k_{j}}{4}$
$= \frac{60 \times 120}{4} = 1800$

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Average free flow speed and the jam density observed on a road stretch are 60 km/h and 120 vehicles/ km, respectively. For a linear speed density relationship, the maximum flow on the road stretch (in vehicles/h) is 1800

The correct option is A 1800Vf=60km/h kj=120veh/km qmax=Vfkj4 =60×1204=1800

Average free flow speed and the jam density observed on a road stretch are 60 km/h and 120 vehicles/ km, respectively. For a linear speed density relationship, the maximum flow on the road stretch (in vehicles/h) is

1800

The correct option is A 1800
$V_{f} = 60 k m / h$
$k_{j} = 120 v e h / k m$
$q_{m a x} = \frac{V_{f} k_{j}}{4}$
$= \frac{60 \times 120}{4} = 1800$