Average life time of a nuclei $T_{a v}$ = $x t_{1 / 2}$ . The value of $x$ is :

1.44

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2.88

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0.72

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none of these

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Solution

The correct option is C 1.44
Average life time of a nuclei, if $T_{a v} = t_{1 / 2}$ is $1.44$ .

$k = \frac{0.693}{t_{1 / 2}}$ ......(1)
$T_{a v} = \frac{1}{k}$ ......(2)
From 1 and 2 equation;

$T_{a v} = \frac{t_{1 / 2}}{0.693} = \frac{1}{0.693} t_{1 / 2}$
$\frac{1}{0.693} = 1.44$

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Average life time of a nuclei Tav = xt1/2. The value of x is :

The correct option is C 1.44Average life time of a nuclei, if Tav=t1/2 is 1.44. k=0.693t1/2......(1) Tav=1k......(2)From 1 and 2 equation; Tav=t1/20.693=10.693t1/2 10.693=1.44

Average life time of a nuclei $T_{a v}$ = $x t_{1 / 2}$ . The value of $x$ is :

The correct option is C 1.44
Average life time of a nuclei, if $T_{a v} = t_{1 / 2}$ is $1.44$ .

$k = \frac{0.693}{t_{1 / 2}}$ ......(1)
$T_{a v} = \frac{1}{k}$ ......(2)
From 1 and 2 equation;

$T_{a v} = \frac{t_{1 / 2}}{0.693} = \frac{1}{0.693} t_{1 / 2}$
$\frac{1}{0.693} = 1.44$