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Byju's Answer
Standard XII
Chemistry
Law of Mass Action
Average rate ...
Question
Average rate of reaction
2
S
O
2
(
g
)
+
O
2
(
g
)
→
2
S
O
3
(
g
)
is written as :
A
△
[
S
O
2
]
△
t
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B
−
△
[
O
2
]
△
t
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C
1
2
△
[
S
O
2
]
△
t
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D
△
[
S
O
3
]
△
t
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Solution
The correct option is
C
−
△
[
O
2
]
△
t
Average rate of reaction
2
S
O
2
(
g
)
+
O
2
(
g
)
→
2
S
O
3
(
g
)
is written as :
Rate,
r
=
−
△
[
O
2
]
△
t
=
−
1
2
△
[
S
O
2
]
△
t
=
1
2
△
[
S
O
3
]
△
t
.
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4
Similar questions
Q.
2
S
O
3
(
g
)
⇋
2
S
O
2
(
g
)
+
O
2
(
g
)
The conventional equilibrium constant expression (
K
c
) for the system as described by the above equation is:
Q.
For the reaction,
2
S
O
2
(
g
)
+
O
2
(
g
)
⇌
2
S
O
3
(
g
)
What is
K
c
when the equilibrium concentration of
[
S
O
2
]
=
0.60
M
,
[
O
2
]
=
0.82
M
and
[
S
O
3
]
=
1.90
M
?
Q.
The oxidation of
S
O
2
by
O
2
to
S
O
3
is an exothermic reaction according to equation
2
S
O
2
(
g
)
+
O
2
(
g
)
⇌
2
S
O
3
(
g
)
+
Heat
. The yield of
S
O
3
will be maximum if
Q.
Assertion :The
Q
c
for the reaction:
2
S
O
2
(
g
)
+
O
2
(
g
)
⇋
2
S
O
3
(
g
)
is
Q
c
=
[
S
O
3
]
2
[
S
O
2
]
2
[
O
2
]
Reason: When
Q
c
<
K
c
, the reaction is not at equilibrium and it will fast in backward direction.
Q.
K
p
value for
2
S
O
2
(
g
)
+
O
2
(
g
)
⇌
2
S
O
3
(
g
)
is
5.0
a
t
m
−
1
. What is the equilibrium partial pressure of
O
2
if the equilibrium pressures of
S
O
2
and
S
O
3
are equal?
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