Question

Average value of Poisson's ratio for a mixture of two mol of each gas A and B is $1.66$, then average molar heat capacity at constant V is:

• A. -3 cal
• B. -1 cal
• C. 3 cal
• D. None of these

Answer 1

The correct option is C 3 cal

$(a,c)$ ${\rm Y}$ for mono-atomic is $1.66$.
$\therefore$ $C_V=\frac{3R}{2},C_P=\frac{5}{2}R$
$C_{VM}=\frac{2\times \frac{3R}{2}+2\times \frac{3R}{2}}{4}$
$\therefore$ $C_V=3cal$