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Question

ax2+2y2+2bxy+2x−y+c=0 represents a circle through the origin, if

A

a = 0, b = 0, c = 2

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B
a = 1, b = 0, c = 0
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C
a = 2, b = 2, c = 0
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D
a = 2, b = 0, c = 0
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Solution

The correct option is D a = 2, b = 0, c = 0
We know the condition for a second degree curve to be a circle which is, a = b and h = 0
which gives us a = 2, b = 0
Also here, we have to check the condition for circle to pass through origin i.e. origin satisfies equation of circle or c = 0.

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