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Quadratic Equation

a x∧ 2+b x+c=...

Question

ax^2 +bx +c=k(x-alpha)(x-beta)

What does this equation mean why k has been taken as a constant and for more details alpha and beta are the zeroes of the polynomial p(x)=ax^2 +bx+c

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Solution

If you already know the roots of a quadratic equation and you want to find out the equation. This equation can be applied.
P(x) = K(x-apha)(y-beta)

The k is a constant, for finding the equation, we need k, it will be given.
There are other methods of finding quadratic equation, we can also use that.
Basically this is just a form of writing the equation

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Similar questions

Q. For a quadratic polynomial

p (x) = a x^{2} + b x + c, α + β = 2

α β = - 8

α, β

p (x)

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∴

a, b

c

is ________ respectively.

α

β

are the zeroes of the quadratic polynomial

a x^{2} + b x + c

α + β = \frac{- b}{a}

α β = \frac{c}{a}

.

Q. For the zeroes

α

β

P (x) = a x^{2} + b x + c, \frac{1}{α} + \frac{1}{β} =

Q. If roots of the equation

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, then evaluate:

α^{2} + β^{2}

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