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Question

ax+bcx+d5.

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Solution

Consider the function,

f( x )= ax+b cx+d

The quotient rule of derivative to find the derivative of the function is,

d dx ( U V )= ( U V V U ) V 2

Where U and V are the derivative of their respective functions.

Apply quotient rule of derivative in the given function,

f ( x )= ( cx+d ) d dx ( ax+b )( ax+b ) d dx ( cx+d ) ( cx+d ) 2 = ( cx+d )a d dx x( ax+b )c d dx x ( cx+d ) 2 = ( cx+d )a( ax+b )c ( cx+d ) 2

Further simplify,

f ( x )= ( acx+adacxbc ) ( cx+d ) 2 = adbc ( cx+d ) 2

Thus, the derivative of ax+b cx+d is adbc ( cx+d ) 2 .


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