ax + by = 0

Find the values of x and y which always satisfy the above equation.

(x, y) =

(0, 0)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1, 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2, 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(5, 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A (0, 0)
ax + by = 0

x = 0 and y = 0, always satisfy the above equation. If the 'c' is '0' (ax + by + c = 0) then the straight line always passes through the origin.

ax + by
= $(a \times 0) + (b \times 0) = 0$

Suggest Corrections

Similar questions

\frac{2}{x} + \frac{2}{3 y} = \frac{1}{6}

\frac{3}{x} + \frac{2}{y} = 0

y = a x - 4

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 6, \frac{2}{x} - \frac{3}{y} + \frac{4}{z} = 8

\frac{3}{x} - \frac{4}{y} + \frac{5}{z} = 10

x

y

z

\begin{matrix} x & 1 & 2 & 3 & 4 & 5 & 6 y & 5 & 9 & 15 & 23 & 33 & 45 \end{matrix}

x + y = 18 and x - 2 y = 0

Find the value of x and y .

Join BYJU'S Learning Program