Axis of the parabola $x^{2} - 4 x - 3 y + 10 = 0$ is

y + 2 – 0

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x + 2 – 0

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y – 2 = 0

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x – 2 = 0

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Solution

The correct option is D x – 2 = 0
The parabola is $(x - 2)^{2} = (3 y - 6)$ . Hence axis is x – 2 = 0.

Suggest Corrections

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x^{2} - 4 x - y + 1 = 0

The equation of the directrix of the parabola $x^{2} - 4 x - 3 y + 10 = 0$ is

x^{2} - 4 x - 3 y + 10 = 0

x^{2} + 4 x + 2 y = 0

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