Question

$B_2{H}_6$ reacts with $O_2$ and $H_{2}O$ respectvely to form:

• A. $B_2{O}_3,H_{3}B{O}_3$
• B. $B_2{O}_3,B{H}_4$
• C. $HB{O}_2,H_{3}B{O}_3$
• D. $H_{2}B{O}_3,HB{O}_2$

Answer 1

The correct option is A $B_2{O}_3,H_{3}B{O}_3$

Diborane catches fire spontaneously upon exposure to air. When diborane $\left(B_2{H}_6\right)$ reacts with oxygen (or air) burns spontaneously to produce a large amount of heat. Thus, the reaction is exothermic. The reaction which takes place is:

$B_2{H}_6+3O_2\to B_2{O}_3+3H_{2}O$
$\Delta H=–1976KJmo{l}^{–1}$

Diborane react with water to form boric acid.
$B_2{H}_6+6H_{2}O\to 2H_{3}B{O}_3+6H_2$