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Summation by Sigma Method

b-a-b b b-a a...

Question

b-a-b b b-a a-b-b a-

a a a b b a

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a b a b a a

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b b a a a b

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a b a a b b

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b a b b b a

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Solution

The correct option is E b a b b b a
bbaabb have been repeated twice and bbaa
are left in the last Had there been more letters
in the series bbaabb would have been formed.

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