b - a - bab - ab - a

abab

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abbb

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baba

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bbab

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aaab

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Solution

The correct option is A abab
abab is correct option

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Similar questions

\begin{matrix} A & B \\ \times & B & A \end{matrix} \begin{matrix} (B + 1) & C & B \end{matrix}

A

B

A + B = A B,

(a + \frac{a b}{a - b}) (\frac{a b}{a - b} - a) : \frac{a^{2} + b^{2}}{a^{2} - b^{2}}

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