Dear Student,
(i) Frequency of the horn, v= 400Hz
Speed of the train, vT=10m/s
Speed of sound, v= 340m/s
The apparent frequency (v′) of the horn as the train approaches the platform is given by the
relation: v′=(v−vrv)v
=(340−10340)×400=412.12Hz
(ii) The apparent frequency (v′) of the horn as the train recedes from the platform is given by the relation:
v′′=(v+vrv)v
=(340+10340)×400=388.57Hz
Regards.