Question 57 (b)
Add the following expression:
x3−x2y−xy2−y3 and x3−2x2y+3xy2+4y
We have,x3−x2y−xy2−y3 and x3−2x2y+3xy2+4y On combining the like terms, = x3+x3−x2y−2x2y−xy2+3xy2−y3+4y= 2x3−3x2y+2xy2−y3+4y
Question 58 (c)
Subtract:
−4x2y−y3 from x3+3xy2−x2y.