Question

Question 1(b)

Find the sum by suitable rearrangement:
1962 + 453 + 1538 + 647

Answer 1

We can arrange the calculation in such a way that it becomes easy and quick to find the answer.

1962 + 453 + 1538 + 647 can be represented as:

=(1962+1538)+(453+647)

We club (1962 and1538) together as their last 2 digits add up to 10. Similarly, the sum of (453 and 647) will also have 0 in the last digit.

Then the sum of these two parts becomes easier and more intuitive.

=(1962+1538)+(453+647)

=3500+1100

=4600