Question 67 (b)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

$m^{2} + n^{2} + p^{2}$

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Solution

Given, m = 1, n = -1 and p = 2
So, putting m = 1, n = -1 and p = 2 in the given expression, we get
$m^{2} + n^{2} + p^{2} = (1)^{2} + (- 1)^{2} + (2)^{2} = 1 + 1 + 4 = 6$

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Similar questions

Question 67 (a)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

m + n + p

Question 67 (c)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

$m^{3} + n^{3} + p^{3}$

Question 67 (d)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

mn + np + pm

m^{2} n^{2} + n^{2} p^{2} + p^{2} m^{2}

m^{2} + 6 n

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