Question

Question 4 (b)
How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of
(b) 1 $\Omega$ ?

Answer 1

(b) The following circuit diagram shows the connection of the three resistors.

All the resistors are connected in series.
Therefore, their equivalent resistance will be given as
$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$
$\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3+2+1}{6}=\frac{6}{6}=1\Omega$
$R=1\Omega$
Therefore, the total resistance of the circuit is $1\Omega$.