B is an extremity of the minor axis of the ellipse whose foci are S and S′. If ∠SBS′ is a right angle, then eccentricity of the ellipse is
A
12
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B
1√2
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C
23
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D
13
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Solution
The correct option is B1√2
Coordinates of S=(ae,0) and S′=(−ae,0)
whereas coordinate of B(0,b)
From above image OS=OS′ ∠OSB=45°
From tan45°=bae⇒b=ae ⇒b2=a2e2 ⇒a2(1−e2)=a2e2⇒e=1√2