1
Question
_ b n t _ _ n a rn _ n a b _ _ a _ _ _ _
1 3 _ 2 5 3 _ _ 5 2 4 _ 3 2 5 _ _ _ _ _
The last five terms in the series are
_ b n t _ _ n a rn _ n a b _ _ a _ _ _ _
1 3 _ 2 5 3 _ _ 5 2 4 _ 3 2 5 _ _ _ _ _
The last five terms in the series are
Open in App
Solution
The correct option is B 13452
By taking a=1,b=3,m=5,n=4andt=2. The number series runs as 13425, 34152, 41325 and 13452. By dividing the whole series in the group of five digits we find that the first digit of the first group is the third digit of the second group and the last two digits have exchanged their position . The same rule applies in other group also.
By taking a=1,b=3,m=5,n=4andt=2. The number series runs as 13425, 34152, 41325 and 13452. By dividing the whole series in the group of five digits we find that the first digit of the first group is the third digit of the second group and the last two digits have exchanged their position . The same rule applies in other group also.
Suggest Corrections
0
Similar questions