BLindlar- R-C- C-RNa-NH3-A A and B are geometrical isomers R-CH-CH-R- where-

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The Cannizaro Reaction

BLindlar⟵ R-C...

Question

$B L i n d l a r ⟵ R - C \equiv C - R N a / N H_{3} ⟶ A$

A and B are geometrical isomers $(R - C H = C H - R)$ , where-

A is trans and B is cis

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A and B both are cis

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A and B both are trans

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A is cis, B is trans

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Solution

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Similar questions

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B

(R - C H = C H - R)

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

C H_{2} - C H = C H_{3}

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H = C = C H - C H_{3}

C H_{3} - C H = C = C = C H - C H_{3}

A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B

(R - C H = C H - R)

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