A and B are geometrical isomers (R−CH=CH−R), where-
A
A is trans and B is cis
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B
A and B both are cis
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C
A and B both are trans
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D
A is cis, B is trans
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Solution
The correct option is B A is trans and B is cis Both of these reactions are partial reduction of alkyne so both give (R−CH=CH−R)− as product but in presence of Lindlar's catalyst syn addition of H2 - cis product and in presence of Na/Liq.ammonia anti addition of H2 - trans product. So product formed are geometrical isomers (cis/trans).