B -1-47- find - b -A- b-27B- b-47C- b-40D- b-47

The correct option is B b = 47 ( 47) × ( 1) = 47 [ ∵47/ 1 = ( 47) ] b = 47 ...

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Multiplication of Negative Numbers

b ×-1=47, fin...

Question

b $\times$ (-1) = 47, find 'b'.

b = -47

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b = -27

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b = 47

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b = -40

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Solution

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n (A \cup B)

n (A) = 115, n (B) = 326, n (A - B) = 47

n (A + B)

If A and B are two sets such that n(A) = 115, n(B) = 326, $n (A - B)$ = 47, then writen $(A \cup B)$ .

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