B PhNO2 A- The products A and B are-

The correct option is C Ph N=N Ph #160; #160; amp; #160; #160;PhNH _2 Option (C) is the correct answer.When nitrobenzene is reduced with lithiu ...

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Standard XII

Chemistry

General Mechanism of Electrophilic Aromatic Substitution

B PhNO2 A. ...

Question

(B) $H_{2} / N i \leftarrow --- - P h N O_{2} L A H - -- \to$ (A). The products (A) and (B) are:

PhNH

_{2}

& PhNH

_{2}

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Ph-N=N-Ph & Ph-N=N-Ph

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Ph-N=N-Ph & PhNH

_{2}

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Ph-NH-NH-Ph & PhNH

_{2}

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Solution

The correct option is C Ph-N=N-Ph & PhNH $_{2}$
Option (C) is the correct answer.
When nitrobenzene is reduced with lithium aluminiumhydride, azobenzene is obtained.
$P h N O_{2} L A H - -- \to P h - N = N - P h (A)$
However, the catalytic hydrogenation of nitrobenzene gives aniline.
$P h N O_{2} H_{2} + N i - --- \to P h N H_{2} (B)$

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(B) H2/Ni←−−−−PhNO2LAH−−−→ (A). The products (A) and (B) are:

The correct option is C Ph-N=N-Ph & PhNH2Option (C) is the correct answer.When nitrobenzene is reduced with lithium aluminiumhydride, azobenzene is obtained. PhNO2LAH−−−→Ph−N=N−Ph(A)However, the catalytic hydrogenation of nitrobenzene gives aniline. PhNO2H2+Ni−−−−→PhNH2(B)

(B) $H_{2} / N i \leftarrow --- - P h N O_{2} L A H - -- \to$ (A). The products (A) and (B) are: