B R-C- C-RAIf A and B are geometrical isomers RCH-CHR- then-

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Standard XII

Chemistry

Physical Properties of Alkynes

B R-C≡ C-RAIf...

Question

$B L i n d l a r c a t a l y s t / H_{2} \leftarrow ----------- - R - C \equiv C - R N a / N H_{3} - ---- \to A$
If A and B are geometrical isomers $(R C H = C H R) .$ then:

A is cis, B is trans

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A is trans, B is cis

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A and B both are cis

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A and B both are trans.

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Solution

The correct option is B A is trans, B is cis
Cis product is obtained when we use Lindlar's catalyst and trans product is obtained when we use Na/liq. $N H_{3}$ or $L i A l H_{4}$ .

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Similar questions

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B

Where, A and B are geometrical isomers

(R - C H = C H - R)

.
Choose the correct option from the following:

Q. Select the correct statement for

[M (A B) b_{2} c d]

Which of the following statements is correct regarding the chirality (optical isomerism) of the cis and trans isomers of the type $M (a a)_{2} b_{2}$ (M stands for a metal, a and b are achiral ligands and aa is a bidentate ligand) ?

First, you name both the compounds. Yes, both of them have the same name. Yet, are they really the same structure, or they are somehow different? Careful inspection should convince you that they are indeed different. Now, how their physical and chemical properties differ? Generally,
i) Cis-isomer has more dipole moment than trans-isomer.
ii) Cis is less stable than trans.
iii) The boiling points of cis isomers are more than those of trans isomers (remember boiling points are directly related to polarity which is determined by dipole moment).
iv) Chemical reactivities of cis and trans also differ from each other.

Which of the following compounds exhibit geometrical isomerism?

(A)

C H_{2} - C H = C H_{3}

(B)

C H_{3} - C H = C H - C H_{3}

(C)

C H_{3} - C H = C = C H - C H_{3}

(D)

C H_{3} - C H = C = C = C H - C H_{3}

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BLindlar catalyst/H2←−−−−−−−−−−−−R−C≡C−RNa/NH3−−−−−→AIf A and B are geometrical isomers (RCH=CHR). then:

The correct option is B A is trans, B is cisCis product is obtained when we use Lindlar's catalyst and trans product is obtained when we use Na/liq. NH3 or LiAlH4.

$B L i n d l a r c a t a l y s t / H_{2} \leftarrow ----------- - R - C \equiv C - R N a / N H_{3} - ---- \to A$
If A and B are geometrical isomers $(R C H = C H R) .$ then:

The correct option is B A is trans, B is cis
Cis product is obtained when we use Lindlar's catalyst and trans product is obtained when we use Na/liq. $N H_{3}$ or $L i A l H_{4}$ .