B Lindral - H 2- R - C - C - R Na - NH 3- A and B are geometrical isomers R - CH - CH - R -A- A is cis- B is transB- A is trans- B is cisC- A and B both are cisD- A and B both are trans

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Nucleophilic Substitution in Alkyl Halides

B Lindral / H...

Question

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

A is cis, B is trans

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A is trans, B is cis

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A and B both are cis

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A and B both are trans

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Solution

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A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B

(R - C H = C H - R)

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

B L i n d l a r ⟵ R - C \equiv C - R N a / N H_{3} ⟶ A

(R - C H = C H - R)

C H_{2} - C H = C H_{3}

C H_{3} - C H = C H - C H_{3}

C H_{3} - C H = C = C H - C H_{3}

C H_{3} - C H = C = C = C H - C H_{3}

[M (A B) b_{2} c d]

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