B R-C- C-R A and B are geometrical isomers R - CH - CH - R-

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Chain Isomerism

B R-C≡ C-R A ...

Question

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

A and B both are trans

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A is cis, B is trans

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A is trans, B is cis

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A and B both are cis

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Solution

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$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

B L i n d l a r ⟵ R - C \equiv C - R N a / N H_{3} ⟶ A

(R - C H = C H - R)

A L i n d l a r^{'} s \leftarrow ---- - Catalyst R - C \equiv C - R Birch reduction ⟶ B

(R - C H = C H - R)

$B L i n d r a l / H_{2} \leftarrow ------ - R - C \equiv C - R N a / N H_{3} - ---- \to$ A and B are geometrical isomers (R - CH = CH - R):

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