Question

${\mathrm{B}}_2{\mathrm{H}}_6$reacts with ${\mathrm{O}}_2$ and ${\mathrm{H}}_2\mathrm{O}$ respectively to form

• A. ${\mathrm{B}}_2{\mathrm{O}}_3,{\mathrm{H}}_3{\mathrm{BO}}_3$
• B. ${\mathrm{B}}_2{\mathrm{O}}_3,{\mathrm{BH}}_4^{-}$
• C. ${\mathrm{HBO}}_2,{\mathrm{H}}_3{\mathrm{BO}}_3$
• D. ${\mathrm{H}}_3{\mathrm{BO}}_3,{\mathrm{HBO}}_2$

Answer 1

The correct option is A

${\mathrm{B}}_2{\mathrm{O}}_3,{\mathrm{H}}_3{\mathrm{BO}}_3$

The explanation for the correct option:

${\mathrm{B}}_2{\mathrm{H}}_6$reacts with ${\mathrm{O}}_2$ to form a basic oxide and ${\mathrm{B}}_2{\mathrm{H}}_6$ hydrolysis to give Boric acid.

${\mathrm{B}}_2{\mathrm{H}}_6+3{\mathrm{O}}_2\to {\mathrm{B}}_2{\mathrm{O}}_3+3{\mathrm{H}}_2\mathrm{O}$

${\mathrm{B}}_2{\mathrm{H}}_6+6{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{H}}_3{\mathrm{BO}}_3+3{\mathrm{H}}_2$

Hence, option(A) is correct.