The correct option is B baccThe series is #160;b #160;a #160;b #160;c / #160;b #160;a b #160;c #160;/ #160;b #160;a b #160;c #160;. ...

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Electronic Configuration of d-Block Elements

ba - cb - b -...

Question

ba - cb - b - bab

acbb

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bacc

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bcaa

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cabb

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Solution

The correct option is B bacc
The series is b a b c / b a b c / b a b c .

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Similar questions

\frac{(x + b) (x + c)}{(b - a) (c - a)} + \frac{(x + c) (x + a)}{(c - b) (a - b)} + \frac{(x + a) (x + b)}{(a - c) (b - c)} = 1

∣ ∣ ∣ ∣ ∣ \begin{matrix} (b + c)^{2} & b a & a c b a & (c + a)^{2} & c b c a & c b & (a + b)^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣

a, b,

c

(a b + b c) (- c b + b a) + (b c + c a) (- a c + c b) + (c a + a b) (a c - b a)

Factorise the term $a^{2} + b c + a b + a c$

a (a - b) (a - c) + b (b - c) (b - a) + c (c - a) (c - b)

a^{2} (a - b) (a - c) + b^{2} (b - c) (b - a) + c^{2} (c - a) (c - b)

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