Question

$Ba{O}_2\left(s\right)\rightleftharpoons BaO\left(s\right)+O_2\left(g\right);\Delta H=+ve$.

In equilibrium condition, pressure of $O_2$ depends on:

• A. increased mass of $Ba{O}_2$
• B. increased mass of $BaO$
• C. increased temperature of equilibrium
• D. increased mass of $Ba{O}_2$ and $BaO$ both

Answer 1

The correct option is C increased temperature of equilibrium

The pressure of $O_2$ does not depend on concentration terms of other reactants (because both are in solid-state) since this is an endothermic reaction.

If the temperature is raised dissociation of $Ba{O}_2$ would occur more $O_2$ is produced at equilibrium, the pressure of $O_2$ increases.

Hence, option $C$ is correct.