Question

Babita purchased a rectangular plot of length $400$ m and breadth $200$ m.

Her sister Saloni purchased another plot of square shape of side length $300$ m.

Whose plot is having larger in area?

Answer 1

Step 1: Finding the area of Babita's rectangular plot.

Given: Length$\left(\mathrm{l}\right)$ of rectangular plot $=400$m and breadth $\left(\mathrm{b}\right)$of rectangular plot $=200$ m.

Since, Area of rectangular$=\mathrm{l}\times \mathrm{b}$

So, area of rectangular plot of Babita

$$\begin{gathered} =400\times 200 \\ =80000{\mathrm{m}}^2 \end{gathered}$$

Step 2: Finding the area of Saloni's square plot.

Side $\left(\mathrm{s}\right)$ of square plot $=300\mathrm{m}$

Since, Area of square $=\mathrm{s}\times \mathrm{s}$

So, area of square plot of Saloni's plot

$$\begin{gathered} =300\times 300 \\ =90000{\mathrm{m}}^2 \end{gathered}$$

We can see that $90000>80000$

Hence, Saloni's plot is larger in area compared to Babita.