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Question

Babubhai borrows Rs 4000 and agrees to repay with a total interest of Rs. 500 in 10 installments, each installment being less than the preceding installment by Rs. 10, what should be the first and last installment?

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Solution

Total money repaid by Babubhai in 1010 Interest
S10=4000+500
S10=Rs.4500
∵ He repays each instalment being less than the preceding instalment by Rs. 1010
∴ Difference between two consecutive installments d=10
We know that,
Sn=n2[2a+(n1)d]
S10=102[2a+(101)d]
4500=5[2a+9(10)]
900=2a90
900+90=2a
990=2a
a=495
Now, tn=a+(n1)dtn=a+(n1)d
t10=a+(101)dt10=a+(101)d
t10=495+9(10)
10=49590
t10=405

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