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Question

Bag B1 contains 4 white and 2 black balls. Bag B2 cantains 3 white and 4 black balls. A bag is drawn at random and a ball is chosen at random from it. What is the probability that the ball drawn is white?

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Solution

Let E denote the event of drawing while ball
P(E)=P(B1)P(E/B1)+P(B2)P(E/B2)
=12×46+12×37=12(23+37)=12(14+921)=2342.

1214862_1396584_ans_633f43e6dce54d488ee1c76a2753b2ed.jpg

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