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Question

Bag I contains 3 black and 2 white balls, bag II contains 2 black and 4 white balls, bag III contains 4 black and 4 white balls. A bag and a ball is selected at random. Determine the probability of getting a black ball.

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Solution

Let E1= Event that bag I is selected
E2= Event that bag II is selected
E3= Event that bag III is selected
E = Event that selected ball is black
P(E | E1) =P(selected ball is black given that bag I is selected)= 35
P(E | E2) =P(selected ball is black given that bag II is selected)= 26
P(E | E3) =P(selected ball is black given that bag III is selected)= 48
P(E1) = P(E2) =P(E3) = 13
P(E) = P(E | E1)×P(E1)+P(E | E2)×P(E2)+P(E | E3)×P(E3)
P(E) = 35×13+26×13+48×13 = 4390

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