Bag I contains 3 black and 2 white balls, bag II contains 2 black and 4 white balls, bag III contains 4 black and 4 white balls. A bag and a ball is selected at random. Determine the probability of getting a black ball.
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Solution
Let E1= Event that bag I is selected E2= Event that bag II is selected E3= Event that bag III is selected E = Event that selected ball is black P(E|E1)=P(selectedballisblackgiventhatbagIisselected)=35 P(E|E2)=P(selectedballisblackgiventhatbagIIisselected)=26 P(E|E3)=P(selectedballisblackgiventhatbagIIIisselected)=48 P(E1)=P(E2)=P(E3)=13 P(E)=P(E|E1)×P(E1)+P(E|E2)×P(E2)+P(E|E3)×P(E3) P(E)=35×13+26×13+48×13=4390