Question

Question 11
Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answer 1

Let Baichung’s age be x years,
Baichung’s father’s age = (x+29) years
Baichung’s granddaughter’s age = (x+29+26) = (x+55) years.

According to condition,
$(x+x+29+x+55=135)$

$\Rightarrow 3x+84=135$
$\Rightarrow 3x+84-84=135-84$ [Subtracting 84 from both sides]

$\Rightarrow 3x=51$
$\Rightarrow \frac{3x}{3}=\frac{51}{3}$ [Dividing both sides by 3]
$\Rightarrow x=17years$

Hence, Baichung’s age = 17 years,
Baichung’s father’s age = 17+ 29 = 46 years
Baichung’s granddaughter’s age = 17+29 + 26 = 72 years.