Balance equation for the reaction of conc. sulphuric acid with glucose:

2 C_{6} H_{12} O_{6} + H_{2} {S O}_{4} (c o n c) \to 6 C + 12 H_{2} O + H_{2} {S O}_{4} (d i l)

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C_{6} H_{12} O_{6} + H_{2} {S O}_{4} (c o n c) \to 3 C + 6 H_{2} O + H_{2} {S O}_{4} (d i l)

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C_{6} H_{12} O_{6} + 2 H_{2} {S O}_{4} (c o n c) \to 6 C + 6 H_{2} O + H_{2} {S O}_{4} (d i l)

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C_{6} H_{12} O_{6} + H_{2} {S O}_{4} (c o n c) \to 6 C + 6 H_{2} O + H_{2} {S O}_{4} (d i l)

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Solution

The correct option is D $C_{6} H_{12} O_{6} + H_{2} {S O}_{4} (c o n c) \to 6 C + 6 H_{2} O + H_{2} {S O}_{4} (d i l)$
The balanced chemical equation is $C_{6} H_{12} O_{6} + H_{2} S O_{4} (c o n c) \to 6 C + 6 H_{2} O + H_{2} S O_{4} (d i l)$ . Concentrated sulphuric acid reacts with one molecule of glucose to form 6 carbon atom, 6 water molecule and one molecule of dil $H_{2} S O_{4}$ So the reaction is perfectly balanced. Hence the correct option is D

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