Balance the chemical reaction of laboratory preparation method of dihydrogen:

Z n + 2 H^{+} ⟶ Z n^{2 +} + H_{2}

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Z n^{2 +} + 2 H^{-} ⟶ Z n + H_{2}

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Z n^{2 +} + 2 H^{+} ⟶ Z n^{2 +} + H_{2}

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None of the above

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Solution

The correct option is A $Z n + 2 H^{+} ⟶ Z n^{2 +} + H_{2}$
Hydrogen is prepared in the laboratory by the action of acids on metals. Dilute sulphuric acid containing 1 volume of concentrated acid to 5 volumes of water, or dilute hydrochloric acid containing 1 volume of concentrated acid to 4 volumes of water, is added to granulated zinc. Zinc sulphate or zinc chloride is formed in solution and the hydrogen that is evolved is collected over water in a trough.
$Z n + 2 H^{+} ⟶ {Z n}^{2 +} + H_{2}$

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Similar questions

In the reaction Zn +2 $H^{+}$ +2 $C l^{-}$ $⟶$ $Z n^{+} 2$ + 2 $C l^{-}$ + $H_{2}$ the spectator ion

$Z n + 2 H^{+} + 2 C l^{-} - - - - - - - > Z n^{2 +} + 2 C l^{-} + H_{2}$

Z n (s) + 2 H^{+} (a q) ⇌ {Z n}^{2 +} (a q) + H_{2} (g)

H_{2} {S O}_{4}

Z n_{(s)} + 2 H^{+} (a q) \to Z n^{2 +} (a q) + H_{2 (g)}

H_{2} S O_{4}

Z n + 2 H^{+} (a q) \to Z n^{2 +} (0.1 M) + H_{2} (g) (1 a t m)

25^{\circ}

(E_{Z n^{2 +} / Z n}^{\circ} = - 0.76

E_{H^{+} / H_{2}}^{\circ} = 0)

E^{o}

{Z n}^{2 +} | Z n

- 0.76

Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ 2 H^{+} (1 M) ∣ ∣ H_{2} (1 a t m)

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