Balance the equation -KMnO 4- H 2 SO 4- FeSO 4 - K 2 SO 4- MnSO 4- Fe 2 SO 43- H 2 O

Mn+7 → Mn+2 ; Fe+2 → Fe2+3 Mn+7 + 5e^ → Mn+2 (1) × 2;2Fe+2 → Fe2+3 + 2e^ (2) × 5 2Mn+7 + 10e^ → 2Mn+2;10Fe2+2 → 5Fe2+3 + 10e^ . Therefore coefficient ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Reactivity with Air and Water (Group 2)

Balance the e...

Question

Balance the equation :
$K M n O_{4} + H 2 S O_{4} + F e S O 4 \to K 2 S O_{4} + M n S O_{4} + F e_{2} (S O_{4})_{3} + H_{2} O$

Open in App

Solution

$M n + 7 \to M n + 2; F e + 2 \to F e 2 + 3 M n + 7 + 5 e^{-} \to M n + 2 (1) \times 2; 2 F e + 2 \to F e 2 + 3 + 2 e^{-} (2) \times 5 2 M n + 7 + 10 e^{-} \to 2 M n + 2; 10 F e 2 + 2 \to 5 F e 2 + 3 + 10 e^{-} .$
Therefore coefficient of $K M n O_{4}$ is 2, that of $M n S O_{4}$ is 2, that of $F e S O_{4}$ is 10 and that of $F e_{2} (S O_{4})$ is 5.
Therefore $2 K M n O_{4} + 10 F e S O_{4} \to 2 M n S O_{4} + 5 F e_{2} (S O_{4})^{3}$
Coefficient of $K_{2} S O_{4}$ should be 1.
$2 K M n O_{4} + 10 F e S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 5 F e_{2} (S O_{4})^{3}$
To balance $S O_{4}^{2 -}$ so that left hand side must have $8 H_{2} S O_{4}$ , thus $H_{2} O$ also becomes $8 H_{2} O$ .
$2 K M n O_{4} + 10 F e S O_{4} + 8 H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n (S O_{4}) + 5 F e_{2} (S O_{4})^{3} + 8 H_{2} O$

Suggest Corrections

Similar questions

K M n O_{4} + H_{2} S O_{4} + F e S O_{4} \to K_{2} S O_{4} + M n S O_{4} + F e_{2} (S O_{4})_{3} + H_{2} O

Coefficients of sulphuric acid and ferric sulphate in the balanced equation of above reaction are______and ______respectively.

Balance the following reaction.

F e C_{2} O_{4} + K M n O_{4} + H_{2} S O_{4} \to F e_{2} (S O_{4})_{3} + C O_{2} + M n S O_{4} + K_{2} S O_{4} + H_{2} O

Q. Identify the correctly balanced redox reaction using ion-electron method.

F e S O_{4} + K M n O_{4} + H_{2} S O_{4} \to F e_{2} (S O_{4})_{3} + M n S O_{4} + H_{2} O + K_{2} S O_{4}

Q. Balance the following equation by oxidation number method.

K_{2} C r_{2} O_{7} + F e S O_{4} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + F e_{2} (S O_{4})_{3} + K_{2} S O_{4} + H_{2} O

Q. Balance the following equation by oxidation number method.

A l + K M n O_{4} + H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + K_{2} S O_{4} + M n S O_{4} + H_{2} O

Join BYJU'S Learning Program

Balance the equation : KMnO4+H2SO4+FeSO4→K2SO4+MnSO4+Fe2(SO4)3+H2O

Balance the equation :
$K M n O_{4} + H 2 S O_{4} + F e S O 4 \to K 2 S O_{4} + M n S O_{4} + F e_{2} (S O_{4})_{3} + H_{2} O$