Question

Balance the following chemical equation:
b) <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${Na}_2$${CO}_3$ + $HCl$ → $NaCl$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $H_{2}O$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${CO}_2$

Answer 1

The skeletal equation is:
<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${Na}_2$${CO}_3$ + $HCl$ → $NaCl$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $H_{2}O$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${CO}_2$

• Count the number of atoms of each element.

• To equalize H, multiply HCl by 2

${Na}_2$${CO}_3$ + $2HCl$ → $NaCl$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $H_{2}O$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${CO}_2$

• To equalize Na and Cl multiply NaCl by 2

${Na}_2$${CO}_3$ + $2HCl$ → $2NaCl$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $H_{2}O$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${CO}_2$

Hence, the equation is balanced.