Balance the following chemical equation:
Balancing of the reaction by trial and error method:
To balance the chemical equation, begin by multiplying the element or compound which has less number of atoms with a number that would make the number equal on both sides.
Left hand side (LHS) is the reactant side and Right hand side (RHS) is the product side.
Type of atoms | Number of atoms on L.H.S. | Number of atoms on R.H.S. |
Sodium (Na) | 1 | 1 |
Nitrogen (N) | 1 | 1 |
Oxygen (O) | 3 | 4 |
Balance the equation by multiplying Sodium nitrate (NaNO3) on LHS with 2 as the number of atoms of Oxygen are less on LHS.
Type of atoms | Number of atoms on L.H.S. | Number of atoms on R.H.S. |
Sodium (Na) | 2 | 1 |
Nitrogen (N) | 2 | 1 |
Oxygen (O) | 6 | 4 |
As the number of atoms is still unequal, multiply Sodium nitrite (NaNO2) with 2.
Type of atoms | Number of atoms on L.H.S. | Number of atoms on R.H.S. |
Sodium (Na) | 2 | 2 |
Nitrogen (N) | 2 | 2 |
Oxygen (O) | 6 | 6 |
As the number of atoms of all elements is equal on both sides, the chemical equation is now balanced.
So, the overall complete and balanced chemical equation is