Balance the following chemical equation-aqCr2O2-7 - aqSO2-3-aqCr3- - aqSO2-4 Acidic medium

So , oxidizing agent : Cr_2O_7 Reducing agent : SO_3 n factor : for Cr_2O_7^2 :6 nbsp; , for SO_3 :2 nbsp; Equalising the decrease/increase nbsp;in ox ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Chemistry

Oxidation Number Method

Balance the f...

Question

Balance the following chemical equation: $C r_{2} O_{7}^{2 -} (a q) + S O_{3}^{2 -} (a q) \to C r^{3 +} (a q) + S O_{4}^{2 -} (a q)$ (Acidic medium)

C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) + H^{+} (a q) \to 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (a q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C r_{2} O_{7}^{2 -} (a q) + S O_{3}^{2 -} (a q) + 8 H^{+} (a q) \to 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (a q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) + 8 H^{+} (a q) \to 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (a q)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) + 8 H^{+} (a q) \to C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (a q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) + 8 H^{+} (a q) \to 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (a q)$

So , oxidizing agent : $C r_{2} O_{7}$
Reducing agent : $S O_{3}$

n-factor :
for $C r_{2} O_{7}^{2 -} : 6$ , for $S O_{3} : 2$
Equalising the decrease/increase in oxidation number :
$C r_{2} O_{7}^{2 -} + S O_{3}^{2 -} \to 2 C r^{+ 3} + S O_{4}^{2 -}$
Cross multiply the oxidising or reducing agent with simplified n-factor number,
$C r_{2} O_{7}^{2 -} + 3 S O_{3}^{2 -} \to 2 C r^{+ 3} + 3 S O_{4}^{2 -}$
Balance oxygen atoms.
$C r_{2} O_{7}^{2 -} + 3 S O_{3}^{2 -} \to 2 C r^{+ 3} + 3 S O_{4}^{2 -} + + 4 H_{2} O$
Balance Hydrogen atoms.
$C r_{2} O_{7}^{- 2} + 3 S O_{3}^{2 -} + 8 H^{+} \to 2 C r^{3 +} + 3 S O_{4}^{2 -} + + 4 H_{2} O$
balance charge
charge in reactant side = 0
charge in product side = 0
so the balanced equation is
$C r_{2} O_{7}^{2 -} + 3 S O_{3}^{- 2} + 8 H^{+} \to 2 C r^{3 +} + 3 S O_{4}^{2 -} + 4 H_{2} O$

Suggest Corrections

Similar questions

Q. What will be the ratio

\frac{n_{C r_{2} O_{7}^{2 -}}}{n_{S O_{3}^{2 -}}}

when the following redox reaction

C r_{2} O_{7}^{2 -} (a q) + S O_{3}^{2 -} (a q) \to C r^{3 +} (a q) + S O_{4}^{2 -} (a q)

is balanced in an acidic medium. Where

n

represents the stoichiometric coefficient of the respective species.

Q. Balance the following redox reactions by ion electron method.

C r_{2} O_{7}^{2 -} + S O_{2} (g) \to C r^{3 +} (a q) + S O_{4}^{2 -} (a q)

(in acidic solution)

Q. Balance the following redox reaction.

(C r_{2} O_{7})_{(a q)}^{2 -} + F e_{(a q)}^{2 +} \to C r_{(a q)}^{3 +} + F e_{(a q)}^{3 +}

(acidic medium)

Write balanced redox reactions of the following:

H_{2} O_{2} (a q)

reduces

{C r}_{2} O_{7}^{2 -} (a q)

to green coloured

{C r}^{3 +} (a q)

in acidic medium.

Balance the following redox equations by oxidation number method.

occur in acidic medium

S n_{(a q)}^{2 +} + I O_{4 (a q)}^{-} \to S n_{(a q)}^{4 +} + I_{(a q)}^{-}

Join BYJU'S Learning Program

Explore more

Oxidation Number Method

Standard XIII Chemistry

Join BYJU'S Learning Program

Balance the following chemical equation:Cr2O2−7(aq)+SO2−3(aq)→Cr3+(aq)+SO2−4(aq) (Acidic medium)

Balance the following chemical equation: $C r_{2} O_{7}^{2 -} (a q) + S O_{3}^{2 -} (a q) \to C r^{3 +} (a q) + S O_{4}^{2 -} (a q)$ (Acidic medium)