Balance the following chemical equation-aqCr2O-27 - aqSO-23-aqCr-3 - aqSO-24 Acidic medium

Steps for Balancing redox reactions: Identify the oxidation nbsp;and nbsp;reduction half nbsp;. Find the oxidising and reducing agent. Find the n fact ...

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Standard XI

Chemistry

Oxidation Number Method

Balance the f...

Question

Balance the following chemical equation: $C r_{2} O_{7}^{- 2} (a q) + S O_{3}^{- 2} (a q) \to C r^{+ 3} (a q) + S O_{4}^{- 2} (a q)$ (Acidic medium)

C r_{2} O_{7}^{- 2} (a q) + 3 S O_{3}^{- 2} (a q) + H^{+} (a q) \to 2 C r^{+ 3} (a q) + 3 S O_{4}^{- 2} (a q) + 4 H_{2} O (a q)

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C r_{2} O_{7}^{- 2} (a q) + S O_{3}^{- 2} (a q) + 8 H^{+} (a q) \to 2 C r^{+ 3} (a q) + 3 S O_{4}^{- 2} (a q) + 4 H_{2} O (a q)

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C r_{2} O_{7}^{- 2} (a q) + 3 S O_{3}^{- 2} (a q) + 8 H^{+} (a q) \to 2 C r^{+ 3} (a q) + 3 S O_{4}^{- 2} (a q) + 4 H_{2} O (a q)

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C r_{2} O_{7}^{- 2} (a q) + 3 S O_{3}^{- 2} (a q) + 8 H^{+} (a q) \to C r^{+ 3} (a q) + 3 S O_{4}^{- 2} (a q) + 4 H_{2} O (a q)

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Solution

The correct option is C $C r_{2} O_{7}^{- 2} (a q) + 3 S O_{3}^{- 2} (a q) + 8 H^{+} (a q) \to 2 C r^{+ 3} (a q) + 3 S O_{4}^{- 2} (a q) + 4 H_{2} O (a q)$
Steps for Balancing redox reactions:

Identify the oxidation and reduction half .

Find the oxidising and reducing agent.

Find the n-factor of oxidising and reducing agent.

Balance atom undergoing oxidation and reduction.

Cross multiply the oxidising or reducing agent with simplified n-factor values.

Balance atoms other than oxygen and hydrogen.

Balancing oxygen atoms

Balancing hydrogen atoms

Balance charge

For acidic medium:
As soon as we add x $H_{2} O$ units, we add 2x $H^{+}$ ions on the opposite side.

$n_{f} = (| O . S ._{P r o d u c t} - O . S ._{R e a c t a n t} | \times number of atom$

Following the above mentioned steps:

Balance atom undergoing oxidation and reduction.
$C r_{2} O_{7}^{- 2} + S O_{3}^{- 2} \to 2 C r^{+ 3} + S O_{4}^{- 2}$
Cross multiply the oxidising or reducing agent with simplified n-factor number,
$C r_{2} O_{7}^{- 2} + 3 S O_{3}^{- 2} \to 2 C r^{+ 3} + 3 S O_{4}^{- 2}$
Balance oxygen atoms.
$C r_{2} O_{7}^{- 2} + 3 S O_{3}^{- 2} \to 2 C r^{+ 3} + 3 S O_{4}^{- 2} + + 4 H_{2} O$
Balance Hydrogen atoms.
$C r_{2} O_{7}^{- 2} + 3 S O_{3}^{- 2} + 8 H^{+} \to 2 C r^{+ 3} + 3 S O_{4}^{- 2} + + 4 H_{2} O$
balance charge
charge in reactant side = 0
charge in product side = 0
so the balanced equation is
$C r_{2} O_{7}^{- 2} + 3 S O_{3}^{- 2} + 8 H^{+} \to 2 C r^{+ 3} + 3 S O_{4}^{- 2} + 4 H_{2} O$

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Similar questions

Q. Balance the following chemical equation:

C r_{2} O_{7}^{- 2} (a q) + S O_{3}^{- 2} (a q) \to C r^{+ 3} (a q) + S O_{4}^{- 2} (a q)

(Acidic medium)

Balance the following redox reactions by ion-electron method:
$M n O_{4}^{-} (a q) + I^{-} (a q) \to M n O_{2} (s) + I_{2} (s)$ (in basic medium)

$M n O_{4}^{-} (a q) + S O_{2} (g) \to M n^{2 +} (a q) + (a q) H S O_{4 (a q)}^{-}$ (in acidic solution)

$H_{2} O_{2} (a q) + F e^{2 +} (a q) \to F e^{3 +} (a q) + H_{2} O (l)$ (in acidic solution)

$C r_{2} O_{7}^{2 -} + S O_{2} (g) \to C r^{3 +} (a q) + S O_{4}^{2 -}$ (aq) (in acidic solution)

Q. What will be the ratio

\frac{n_{C r_{2} O_{7}^{2 -}}}{n_{S O_{3}^{2 -}}}

when the following redox reaction

C r_{2} O_{7}^{2 -} (a q) + S O_{3}^{2 -} (a q) \to C r^{3 +} (a q) + S O_{4}^{2 -} (a q)

is balanced in an acidic medium. Where

n

represents the stoichiometric coefficient of the respective species.

Q. What will be the ratio

\frac{n_{C r_{2} O_{7}^{2 -}}}{n_{S O_{3}^{2 -}}}

when the following redox reaction

C r_{2} O_{7}^{2 -} (a q) + S O_{3}^{2 -} (a q) \to C r^{3 +} (a q) + S O_{4}^{2 -} (a q)

is balanced in an acidic medium. Where

n

represents the stoichiometric coefficient of the respective species.

Q. Balance the redox reaction by Half reaction method.

{F e}^{2 +} (a q) + {C r}_{2} O_{7}^{2 -} (a q) (acid medium) - ------- \to {F e}^{3 +} (a q) + {C r}^{3 +} (a q)

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Oxidation Number Method

Standard XI Chemistry

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Balance the following chemical equation:Cr2O−27(aq)+SO−23(aq)→Cr+3(aq)+SO−24(aq) (Acidic medium)

Balance the following chemical equation: $C r_{2} O_{7}^{- 2} (a q) + S O_{3}^{- 2} (a q) \to C r^{+ 3} (a q) + S O_{4}^{- 2} (a q)$ (Acidic medium)