Balance the following equation by ion electron method.
$A g^{+} + A s H_{3} + H_{2} O \to H_{3} A s O_{3} + H^{+} + A g$

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Solution

$A g^{+} + A s H_{3} + H_{2} O \to H_{3} A s O_{3} + H^{+} + A g$
$e^{-} + A g^{+} ⟶ A g$ $\times 6$ Reduction.
$A s^{- 3} H_{3} ⟶ H_{3} A s^{+ 3} O_{3} + 6 e^{-}$ Oxidation
Balancing the charges and then adding the two equations.
$6 A g^{+} + A s H_{3} ⟶ 6 A g + M_{3} A s O_{3}$
Balancing oxygen,
$6 A g^{+} + A s H_{3} + 3 H_{2} O ⟶ 6 A g + M_{3} A s O_{3}$
Balancing hydrogen,
$6 A g^{+} + A s H_{3} + 3 H_{2} O ⟶ 6 A g + M_{3} A s O_{3} + 6 H^{+}$

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