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Question

Balance the following equation by ion electron method:
CrI3+H2O2+OHCrO24+IO4+H2O.

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Solution

Half reactions
[CrI3+32OHCrO24+3IO4+16H2O+27e]×2
[H2O2+2e2OH]×27
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2CrI3+27H2O2+10OH2CrO24+6IO4+32H2O
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