Balance the following equation by ion electron method
$H_{2} {S O}_{4} + H B r \to {S O}_{2} + {B r}_{2}$

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Solution

$H_{2} S O_{4} + H B r \to S O_{2} + B r_{2}$
$H_{2} S O_{4} \to S O_{2} + 2 H_{2} O$ ...(i)
$+ 2 H^{+} + 2 e^{-}$
$2 H B r \to B r_{2} + 2 H^{+} + 2 e$ ...(ii)
(i) + (ii)
$H_{2} S O_{4} + 2 H B r \to S O_{2} + 2 H_{2} O + B r_{2}$

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