Balance the following equation by ion electron method.
${M n O_{4}}^{-} + H^{+} + H_{2} O_{2} \to M n^{2 +} + H_{2} O + O_{2}$

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Solution

Half reactions
$[M n O_{4}^{-} + 8 H^{+} + 5 e \to M n^{2 +} + 4 H_{2} O] \times 2$
$[H_{2} O_{2} \to 2 H^{+} + O_{2} + 2 e] \times 5$
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$2 M n O_{4}^{-} + 6 H^{+} + 5 H_{2} O_{2} \to 2 M n^{2 +} + 8 H_{2} O + 5 O_{2}$
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