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Ion Electron Method

Balance the f...

Question

Balance the following equation by ion electron method.
$N a_{2} H A s O_{3} + K B r O_{3} + H C l \to N a C l + K B r + H_{3} A s O_{4}$ .

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Solution

The ionic half equations are:
$3 {A s}^{+ 3} - 6 e^{-} \to {3 A s}^{+ 5} {B r}^{+ 5} + 6 e^{-} \to {B r}^{- 1}$
So, the final balanced equation is:
$3 {N a}_{2} H A s O_{3} + K B r O_{3} + 6 H C l \to 6 N a C l + K B r + 3 H_{3} A s O_{4}$

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Q. Balance the following equation.

N a_{2} H A s O_{3} + K B r O_{3} + H C l \to N a C l + K B r + H_{3} A s O_{4}

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3 N a_{2} H A s O_{3} + K B r O_{3} + 6 H C l \to 6 N a C l + K B r + 3 H_{3} A s O_{4}

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