Balance the following equation by ion electron method.
$P_{4} + O H^{-} + H_{2} O \to H_{2} P O_{2}^{-} + P H_{3}$ :

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Solution

Half reactions
$[P_{4} + 8 O H^{-} \to 4 H_{2} P O_{2}^{-} + 4 e] \times 3$
$P_{4} + 12 H_{2} O + 12 e \to 4 P H_{3} + 12 O H^{-}$
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$4 P_{4} + 12 O H^{-} + 12 H_{2} O \to 12 H_{2} P O_{2}^{-} + 4 P H_{3}$
or $P_{4} + 3 O H^{-} + 3 H_{2} O \to 3 H_{2} P O_{2}^{-} + P H_{3}$

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