Balance the following equation by ion electron method.
$Z n + H^{+} + N O_{3}^{-} \to Z n^{2 +} + N H_{4}^{+} + H_{2} O$ .

Open in App

Solution

$4 Z n + N O_{3}^{-} + 10 H^{+} \to 4 Z n^{2 +} + N H_{4}^{+} + 3 H_{2} O$ .

Suggest Corrections

Similar questions

Z n + B r O_{4}^{-} + O H^{-} + H_{2} O \to [Z n (O H)_{4}]^{2 -} + B r^{-}

C u + N O_{3}^{-} + 8 H^{+} \to C u (N O_{3})_{2} + N O + H_{2} O

Z n + N O_{3}^{-} + O H^{-} \to Z n O_{2}^{2 -} + N H_{3} + H_{2} O

{C r_{2} O_{7}}^{2 -} + H^{+} + {C_{2} O_{4}}^{2 -} \to C r^{3 +} + C O_{2} + H_{2} O

{M n O_{4}}^{-} + H^{+} + H_{2} O_{2} \to M n^{2 +} + H_{2} O + O_{2}

Join BYJU'S Learning Program