Balance the following equation by oxidation number method.
$F e_{2} (S O_{4})_{3} + H_{2} S O_{3} + H_{2} O \to F e S O_{4} + H_{2} S O_{4}$

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Solution

10FeSO4 + 2KMnO4 + 8H2SO4 = 5Fe2(SO4)3 +K2SO4 +2MnSO4 + 8H2O

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K_{2} C r_{2} O_{7} + F e S O_{4} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + F e_{2} (S O_{4})_{3} + K_{2} S O_{4} + H_{2} O

K_{2} C r_{2} O_{7} + F e S O_{4} + H_{2} S O_{4} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + F e_{2} (S O_{4})_{3} + H_{2} O

K I + H_{2} S O_{4} \to K_{2} S O_{4} + I_{2} + S O_{2} + H_{2} O

K M n O_{4} + H 2 S O_{4} + F e S O 4 \to K 2 S O_{4} + M n S O_{4} + F e_{2} (S O_{4})_{3} + H_{2} O

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